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Nitrate Mass Balance Calculation <br /> 16475 S Tide Road, Ripon <br /> Data Input: <br /> Effluent Quantity (Q): 250 gals/day Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream(N,,): 35.00 mg/L-N Denitrification (d): 25.0% <br /> Site Area (A): 0.94 Acres Deep Perc. of Rain (R): 2.74 in/yr <br /> Waste Loading(W): 3.58 in/yr <br /> Result: <br /> Mass Balance(Nj: 15.3mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 153% <br /> Equations: <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find W <br /> yr day 7.48 gal 1 year 43,560 ft2 1 ft (A) acre <br /> 3.58 in/yr(site)=250 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/0.94 acres) <br /> N - WN 1( d)+RNb Hantzsche-Fennemore Equation(Ncl <br /> W+R <br /> 15.29 mg/L-N=((3.58 in/yr x 35 mg/L-N x(1-0.25))+(2.74 in/yr x 1 mg/L-N))/(3.58 in/yr+2.74 in/yr) <br /> Variables: <br /> Nc = Average nitrate-N concentration (mg/1) of combined effluent and rainfall percolate(15.29 mg/L-N). <br /> W= Uniform waste water loading for study area(in/yr) (3.58 inches/year). <br /> Nw =Total nitrate-N concentration of waste water percolate(35 mg/L-N). <br /> d = Fraction of nitrate-N loss due to denitrification in the soil(25%). <br /> R= Uniform deep percolation of rainfall (2.74 in/yr). <br /> Nb = Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 35 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 2.74 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> Aftn i og ix <br />