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ARCHIVED REPORTS_XR0008888
Environmental Health - Public
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EHD Program Facility Records by Street Name
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V
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VAN BUREN
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424
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3500 - Local Oversight Program
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PR0545786
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ARCHIVED REPORTS_XR0008888
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Last modified
6/1/2020 2:37:03 PM
Creation date
6/1/2020 2:09:21 PM
Metadata
Fields
Template:
EHD - Public
ProgramCode
3500 - Local Oversight Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0008888
RECORD_ID
PR0545786
PE
3526
FACILITY_ID
FA0004969
FACILITY_NAME
CHASE CHEVROLET
STREET_NUMBER
424
Direction
N
STREET_NAME
VAN BUREN
STREET_TYPE
ST
City
STOCKTON
Zip
95205
CURRENT_STATUS
02
SITE_LOCATION
424 N VAN BUREN ST
P_LOCATION
01
P_DISTRICT
001
QC Status
Approved
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EHD - Public
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' GROUND WATER DRAWDOWN TEST CALCULATIONS <br /> 24-HOUR STEP DRAWDOWN TEST <br />' Chase Van Buren <br /> 424 North Van Buren Street, Stockton, California <br />' 8 GALLONS PER MINUTE PUMPING RATE <br />' Assumptions <br /> A constant ground water pumping rate of 8 gallons per nunute test conducted on <br /> 30 May 2001 <br /> • Wells are screened entirely through the upper water table <br /> • Homogenous groundwater aquifer characteristics at observation wells EW-4,MW-3,VW-2, <br /> MW-7, VW-4, VW-1, MW-9 and MW-21A and extraction well EW-3 <br />' The Jacobs Straight Line Method (Distance-Drawdown Method) can be utilized to <br /> calculate hydraulic conductivity, transrnissivity(T) and storativlty yield utilizing draw-down <br /> versus distance on serm-logarithmic paper for each well location (Appendix Z) <br />' Where <br />' K=hydraulic conductivity <br /> T = transrmssivity <br /> S = storativlty <br />' Q = constant ground water pumping rate <br /> As = draw-down per 1-logarzthunc cycle <br /> t= time of pump test <br />' ro = intercept of best fit line with the distance axis <br /> b=thickness of aquifer (sewn penetrated or exposed) <br /> L <br />' Calculations <br /> Q = 8 0 GPM; As =0.50 ft.; t= 1,455 minute; ro = 160 ft. <br />' T = 70Q—As ^# 70(8 0 GPM) —0 50 ft= 1,120 ft /day <br /> 1, <br /> 1,120 ft'/day x 1 gpd/ft -- 0 134 ft'/day= 8,360 gpd/ft <br /> S = T(t) — 640 (ro)2 = (1,120 ft2/day)(1,445 nun) — (640)(160)' = 0.099 <br /> K= T — h= 8,360 gpd/ft — 20 feet=418 ft/day <br /> 418 ft/day(1 cm/sec/2835 ft/day) = 0.147 cm/sec <br /> 1 <br />
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