Laserfiche WebLink
100,ug/1 <br /> Mass= (1,005 ft2*40 feet)*(100µg/1)*(28 32 L/ft3)*(35%)*(1g/1,000,000µg) <br /> =39 85 grams <br />' =0 04 kilogram(0 088 pound) <br /> 1,000,ug/l <br /> Mass=(650 ft2*40 feet)*(1,000µg/1)*(28 32 L/ft3)* (35%)*(1g/1,000,000µg) <br /> =257 7 grams <br /> t =0 258 kilogram(0 569 pound) <br /> 10,000 Pg/L <br /> Mass=(154 ft2*40 feet)*(10,000 gg/1)*(28 32 L/ft3)*(35%)*(1g/1,000,000µg) <br /> =610 6 grams <br /> =0 611 ktIogram(135 pounds) <br /> Total Mass in Ground Water <br /> Total mass =0 04 kg+0 258 kg+ 0 611 kg= 0 91 kg(2 01 pounds) <br /> The calculation indicates that approximately 0 91 kilogram (2 01 pounds) <br /> of TPH-g remains in the ground water at the site This mass would be <br /> equivalent to approximately 2 to 3 pints of gasoline <br /> i <br /> 1 <br /> 1 <br /> 1 <br /> 1 <br /> ERM B-3 9343 50/TJPRR/07/11/02 <br />