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d I Design Example Solution (Cont) <br /> 2(Tan2r)+1(74n32°)+.5(Tan32°) <br /> = Tan_1 3.5 =29.7° <br /> Waste Friction Angle 02 = 25° <br /> Surcharge q = 0 <br /> Radius of Depression rl =3 ft. <br /> Multiaxial Rupture Strain of Liner r R= 10% <br /> Factor of Safety FS = 2 <br /> Design Life Life= 100 years <br /> Step l <br /> B� =2(3ft.)=6ft. <br /> Hcl = 1.0 (fromfigure 2) <br /> Bt <br /> Step 2 <br /> HC1 = 6fl. (1.0) = 6ft. <br /> 01 =Ton (3Jt./6fr.)= 26.6° <br /> (11) <br />