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8.1 Design Example Solution(Cont-) <br /> Sten 7 <br /> T ALL ' 10®/o/2 <br /> ,TALL ` 5% <br /> Step 8 <br /> Q=.97(from Table 2) <br /> TR =2(247Ibs.1sf)(3 ft.K.97) <br /> TR = 1438Ibs.l ft. <br /> Ste} 9 <br /> TSTAT T ALL= 3400 lbs./ft. <br /> FScR= h at 5% S train �J <br /> 100 year Creep Limited Strength at 5%Strain (ASTM D5262) <br /> 3400 lbs/ft. = 1.93 <br /> 1760 lbs/ft. <br /> FSD = 1.0 <br /> FSID = 1.05 (in Clay Backfill) <br /> FS,wr = 1.0 <br /> 3400/bs/ft = 1677 ibs/ft. <br /> LTADS = 1.93xl.Ox1.05xl.0 <br /> to10 <br /> 1677 lbs/ft >t 1438 lbs/ft. ok <br /> (13) <br />