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e lu on <br /> g I Design Exampl So (Cont <br /> Step 7 <br /> TALL a 10%/2 <br /> TALL = 5% <br /> Stay 8 . <br /> Q=.97(from Table 2) <br /> TR =2(247lbslsf)(3ftx.97) <br /> TR =14381bsJ ft. <br /> StgR 9 <br /> TSTAT TALL=3400 ibs./ft. <br /> FSCR= Short Tam jolk Strength at 5%Strain[GRI GGL) <br /> 100 year Creep Limited Strength at 5%Strain (ASTM D5262) <br /> 34001bsJR = 1.93 <br /> 1760 lbs/fL <br /> FSI) = 1.0 <br /> FSEs = 1.05(in Clay Backfill) <br /> FSMT = 1.0 <br /> LTADS= 3400lbs/ft = 1677 lbs/ft <br /> 1.93xl.Ox1.05xl.0 <br /> StPR 10 <br /> 1677 lbslft z 14381bs/ft. ok <br /> (13) <br />