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8.1 Design ExA le <br /> g mp Solution (Cont) <br /> Stpp 3 <br /> r2 = 3ft(6f'--35ft) = 1.25 ft. <br /> 6ft. <br /> to 4 <br /> B2 =2(125ft.) =2.5 ft. <br /> Hct =125 (from figure 2) <br /> B2- <br /> Step 5 <br /> Hct =2.5 ft. (1.25)=3.13 ft. <br /> 02 =TOM-1(I.25fr./3.13,fi.) = 21.8° <br /> Stea 6 <br /> Ta»®l =S0 <br /> Tan92 =.40 <br /> P12 3_(3-3-5(-50))3 <br /> (3`3.5(_50))3 +7 (3-3.5(.50))3 <br /> N -Y3 .50 32(.50) 32(40) <br /> P =247 lbs./ft <br /> N <br /> (12) <br />