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Nitrate Mass Balance Calculation <br /> 14,600 Austin Road, Manteca, CA <br /> Data Input: <br /> Effluent Quantity(Q): 1,361 gals/day Concentration Rain(Nb): 1.0 mg/L-N <br /> Effluent Stream(N„,): 100 mg/L-N Denitrification (d): 35% <br /> Site Area(A): 16.95Acres Deep Perc. of Rain (R): 8.31 in/yr <br /> Waste Loading (W): 1.08 in/yr <br /> Result: <br /> Mass Balance(&): 8.4 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10 mg/L-N <br /> Percent of MCL Nitrate as N 84% <br /> Equations: <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find W <br /> yr day 7.48 gal 1 year 43,560 ftz 1 ft (A) acre <br /> 1.08 in/yr(site)= 1,361 gal/day x(I cu-&1748ga/s)x(365 days/1 year)x(I acre/43,560 sq-ft)x(12 in/1 ft)x(i site/16.95 acres) <br /> N�=WNwL-d)+RNb W+R Hantzsche-Fennemore Equation(NcJ <br /> 8.4 mg/L-N=((1.08 in/yr x 100 mg/L-N x(1-0.35))+(8.31 in/yr x 1 mg/L-N))/(1.06 in/yr+8.31 in/yr) <br /> iriables: <br /> .4c= Average nitrate-N concentration(mg/1)of combined effluent and rainfall percolate(8.4 mg/L-N). <br /> W = Uniform waste water loading for study area (in/yr) (1.08 inches/year). <br /> Nw =Total nitrate-N concentration of waste water percolate(100 mg/L-N). <br /> d = Fraction of nitrate-N loss due to denitrification in the soil (35%, shallow silty sands and deeper clays above groundwater). <br /> R = Uniform deep percolation of rainfall(8.31 in/yr). <br /> Nb = Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 100 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 35%. <br /> 3. Estimated deep percolation of rainfall is 8.31 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br />