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FIELD DOCUMENTS
Environmental Health - Public
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EHD Program Facility Records by Street Name
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2900 - Site Mitigation Program
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PR0541653
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Last modified
7/8/2020 3:43:40 PM
Creation date
7/8/2020 3:35:53 PM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2900 - Site Mitigation Program
File Section
FIELD DOCUMENTS
RECORD_ID
PR0541653
PE
2965
FACILITY_ID
FA0023871
FACILITY_NAME
TOP FILLING STATION
STREET_NUMBER
101
Direction
S
STREET_NAME
WILSON
STREET_TYPE
WAY
City
STOCKTON
Zip
95205
APN
15125307
CURRENT_STATUS
01
SITE_LOCATION
101 S WILSON WAY
P_LOCATION
01
QC Status
Approved
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EHD - Public
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APPENDIX D <br /> SOIL VAPOR EXTRACTED VOLUME-MASS CALCULATIONS <br /> TOP FILLING STATION <br /> 101 South Wilson Way, Stockton, California <br /> Assumptions: <br /> • Utilizing field measurements and analytical data collected from air samples between 18 <br /> March and 17 June 2013, the volume and mass of extracted gasoline hydrocarbons at the <br /> site can be approximated. <br /> The hydrocarbon volume-mass removed during the operating period can be calculated using the <br /> following equation: <br /> M = C • Q • t <br /> where: M = cumulative mass recovered (kg) <br /> C = vapor concentration (kg/m') <br /> Q = extraction flow rate (M3/hr) <br /> t = operational period (hrs) <br /> 1) 18 March 2013 - 23 April 2013 <br /> The average analytical TPH-g concentration for this time interval was determined to be 500 pg/I <br /> (03/13 =800 pg/I, 04/13=200 Ng/I; avg. = 500 pg/1). During this time interval, the average flow rate <br /> was calculated at 2.1 inches of water (2-inch pipe) or approximately 79 cubic feet per minute <br /> (nomograph); the operational period was equal to 860 hours of running time (Table 2). <br /> TPH-g (total petroleum hydrocarbons quantified as gasoline) <br /> C = 500 pg/I = 0.000500 kg/m' <br /> Q = 2.10 inches water = 79 ft' <br /> /min <br /> t = 860 hours (36 days) <br /> Converting Q to m'/hour yields: <br /> Q = (79 ft'/min) • (60 min/hour) • (0.0283168 m'/ft') = 134.2 m'/hour <br /> M = C • Q • t = (0.000500 kg/m') • (134.2 m'/hour) • (860 hours) = 57.7 kg of TPH-g <br /> Converting kg of TPH-g to pounds of TPH-g yields: <br /> 57.7 kg of TPH-g • 2.2046 lbs. of TPH-g/kg of TPH-g = 127.2 lbs of TPH-g <br /> Converting pounds of gasoline to gallons of gasoline yields: <br /> 127.2 lbs. of gas • 0.16 gal of gas/lbs. of gas = 20.4 gallons of gasoline <br /> Advanced CeoEnvironmental,Inc. <br />
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