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' MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS • Assumptions IUtilizing analytical data collected from air samples(Table 3)and from field measurements collected during the SVE pilot test(Table 4),the volume of extracted gasoline hydrocarbons at the site can be approximated The hydrocarbon mass removed during the operating period can be calculated using the followmg equation M=C• Q - t ' where M=cumulative mass recovered(kg) C=vapor concentration(kg/m3) ' Q=extraction flow rate(m'/hr) t=operational period IMass-volume calculations were separated into the following four intervals I) 18 March to 23 March 1999 2) 23 March to 31 March 1999 3) 31 March to 07 April 1999 4) 07 April to April 16 1999 The average TPH-g concentration and flow rates during each time interval was utilized for calculating the approximate extracted gasoline hydrocarbons I18 March to 23 March 1999 1) The average TPH-g concentration during the 8-hour pilot test performed i March 1995 was 18,750µg/1 and ' will be utilized as the start-up TPH-g concentration for the 18 March 1999 since no initial sample was collected,the concentration on 23 March 1999 was 11,000µg/l,the average TPH-g concentration for this time interval is equal to 14,875µg/1 The average flow rate was calculated at 1 19 inches of water,the operational Iperiod was equal to 35 hours of running time C = 14,875µg/l=0 014875 kg/m' f--(Q ; 1 19 inches water= 57 ft3/mine t=35 hours Converting Q to ml/hour yields Q=(57 ft'/mm) -(60 min/hour)-(0 0283168m'/ft)=96 84 ml/hour IM=C - Q-t=(0 014875 kg/m') •(96 84 m'/hour)- (35 hours)=50 5 kg of gas Converting kg of gasoline to pounds of gasoline yields 50 5 kg of gas- 2 2046 lbs of gas/kg of gas= l 11 154 lbs of gas Converting pounds of gasoline to gallons of gasoline yields 1'0 111 154 lbs of gas - 0 16 gal of gas/lbs of gas = 17 78 gallons of gasoline f