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Tank Volume and Secondary Containment Calculations <br /> Tank Volume: <br /> Tank Capacity: volume= (1/3) * 7u * h * (r2 +r * R+R2)where r=1', R=1.5', h=3' 14.42 cu ft <br /> 7.48 gal/cu ft=> 107 gal <br /> Iry <br /> V, <br /> Secondary Containment: <br /> Containment area: 47"x 235"x a minimum of 8"high <br /> 3.92' x 19.58' x .67' = 51.42 cu ft. 57.56 cu ft. * 7.48=>384.66 gal total capacity <br /> Volume of containment area=Total Containment—WOT area—Antifreeze tank area <br /> Vol of WOT: 60: x 30"x 8"= 5' x 2.5' x .67' _> 8.375 cu ft=62.6 gal <br /> Vol of Antifreeze tank: (1/3) * 7c * h * (r2+r * R+RI)where r=1', R=1.5', h=.67' = 3.3 cu ft= <br /> 24.91 gal <br /> Containment area volume: 384.66—62.6-24.91 =297.15 gal total available volume. <br /> Since the Wase Oil tank is double walled tank, the containment are only has to hold the volume <br /> of the antifreeze tank of 100 gal. Containment is large enough. <br /> 47" <br /> Antifreeze tank <br /> 235" <br />