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Mass-Volume Calculation of Dissolved MTBE - 16 March to 14 April 2004 <br /> FLAG CITY CHEVRON - 6421 Capitol Avenue, Lodi, CA <br /> Assumptions <br /> • A total volume of 483,301 gallons was extracted from wells EW-4,EW-5,EW-8 and EW-10 <br /> between 16 March 2004 and 14 April 2004 (based om effluent flow meter observations) <br /> Data collected from the pump and treat influent grab ground water samples were <br /> representative of general extracted ground water conditions <br /> One gallon of water is equivalent to 3 79 liters, so the volume of processed water is given by <br /> V=(483,301 gallons)(3 79 1/gal) = 1,831,710 l processed water <br /> Multiplying the volume of the processed water by the average of the March 2004 and the April 2004 <br /> MTBE concentrations (17 µg/1) yields the approximate mass of MTBE removed from processed <br /> water <br /> MSE = (1,831,7101)(0 000000017 kg/l) = 0.031 kg MTBE (approx. 31 grams) <br /> • A converstion factor oft 205 lb/kg can be used to convert kilograms ofMTBE to pounds of MTBE <br /> MMTBE = (0 031 kg MTBE)(2 205 lb/kg) = 0.07 lb MTBE <br /> Advanced GeoEnvironmental,Inc. <br />