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. Mass-Volume Calculation of Dissolved MTBE - 14 April to 13 May 2004 <br /> FLAG CITY CHEVRON- 6421 Capitol Avenue,Lodi, CA <br /> Assumptions <br /> • A total volume of 325,552 gallons was continuously extracted from wells EW-4, EW-5, <br /> EW-7, EW-8 and EW-10 between 14 April to 13 May 2004(based on effluent flow meter <br /> observations) <br /> • Data collected from the pump and treat influent water samples were representative of general <br /> extracted ground water conditions <br /> One gallon of water Is equivalent to 3 79 liters, so the volume of processed water is given by <br /> V=(325,552 gallons)(3 791/gal) = 1,233,842 I processed water <br /> Multiplying the volume of the processed water by the average of the April 2004 and the May 2004 <br /> MTBE concentrations (17 5 µg/l)yields the approximate mass of MTBE removed from processed <br /> water <br /> Maras=(1,233,8421)(0 0000000175 kg/1)= 0.022 kg 11ITBE (approx. 22 grams) <br /> A converstion factor oft 205 lb/kg can be used to convert kilograms ofMTBE to pounds ofMTBE <br /> MMTBE _ (0 022 kg MTBE)(2 205 lb/kg) = 0.05 lb MTBE <br /> Advanced GeoEnvironmental,Inc. <br />