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Dissolved Mass-Volume Calculations <br /> Page 2 of 3 <br /> AGE-NC-960232 <br /> Vw=(37,718 IV)(7 48 gal/110)=282,128 gallons <br /> One gallon of water weighs 8 337lbs/gal at 60°F, so the west-half mass(M„)of the water in the coned ellipse is given <br /> by <br /> Mw=(282,128 gallons)(8 337 Ib/gal)=2,352,950 lbs <br /> Multiplying Mw by the hydrocarbon concentration yields the approximate mass of dissolved hydrocarbons in the <br /> saturated portion of the inner ellipsoid <br /> M,, (2,352,950 lbsx8 95 • 1 OA}=0.021 lbs gasoline <br /> Dividing M,,=by the weight of one gallon of MTBE (6 17 lbs/gallon)will yield the remaining volume of MTBE <br /> dissolved into the ground water of the inner ellipsoid <br /> VXME=(Mw)/6 17lb/gal)=0 021 lbs/6.17 lbs/gal=0.003 gallons of MTBE <br /> 2) Volume of MTBE-impacted ground water in Eastern Segment Elliptic Cylinder(VF) <br /> • <br /> ii VO <br /> For the eastern segment(V=), <br /> The basal elliptical area,adjoining the western segment aQ=84 ft,ba= 10 ft <br /> The top elliptical area,at northern border of Flag City site a,=50 ft,b,=19 ft <br /> Length of elliptic cylinder. h= 120 ft <br /> Vap,.,w 3 14(120 ft) ((50-84 ft)(19-10 ft)13+ [84 ft(19-10 ft)+ 10 ft(50-84 ft)]/2+(84 ft)(I0 ft)) -4 356,453 fig <br /> Water occupies the porosity in the soil,which is estimated to be 300/c of the soil volume, so the total volume of water <br /> in the saturated portion of coned ellipse is approximated by <br /> Vw=(30)(356,453 ft)= 106,936 fl <br /> One cubic foot of water contains 7 48 gallons,so the volume of the water in the coned ellipse is given by <br /> Adpanced GeoEnvironmrgtal,Inc <br />