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Dissolved Mass-Volume Calculations <br /> • Page 3 of 3 <br /> AGE-NC-960232 <br /> Vw=(106,936 ft)(7 48 gallft)=799,881 gallons <br /> One gallon of water weighs 8 337 lbs/gal at 60°F, so the mass of the water in the coned ellipse is given by <br /> Mw=(799,881 gallons)(8 337 lb/gal)=6,668,604 lbs <br /> Multiplying Mw by the hydrocarbon concentration yields the approximate mass of dissolved hydrocarbons in the <br /> saturated portion of the coned ellipse <br /> M,n.m(6,668,604 lbs)(2 60• 10 7)=1.73 lbs MTBE <br /> Dividing Mw,by the weight ofone gallon ofMTBE(6 17 lbs/gallon)will yield the remaining volume ofMTBE dissolved <br /> into the ground water of the coned ellipse <br /> Vmms(M,4,mF)/6 17lb/gal)= 173 lbs/6 17 lbs/gal=0.28 gallons MTBE <br /> Combining the volumes of MTBE-impacted ground water from the western and eastern plume <br /> segments yield a total of approximately 1.75 lbs MTBE at the site, or equivalent to 0.283 gallons <br /> MTBE <br /> i <br /> Advanced GeoEnnronmental,Inc <br />