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u <br /> addifion to <br /> the mtroduction of <br /> of alkalinity for eve wastes. As referenced, <br /> water exhibited r1'mg°f ammonia-nitrogen nitrification cons <br /> higher alkali (NH4-N)oxidized. Sampled <br /> yes approximately mh'than the water table City o fM Y 7.1 mg <br /> Nitrification of the average Total Nitrogen groundwater(217 m anteca <br /> 8�- vs. 145 mg/L). <br /> Section IV would require: 87 m g ( �concentration of 87 m <br /> alkalinity in the domestic water NH4-N x 7.1 mg CaCO — g� determined below in <br /> supply is deficient if the ' —618 mg/I alkalinity herefore the <br /> nitrification may be inhibited. TN will be equal to 87 <br /> PPm, and <br /> C. Mounding Analysis <br /> Reference is made to the encountered groundwater table at 10 feet below existing grade. This <br /> shallow groundwater table may induce a phenomenon known as the mounding effect. A procedure <br /> developed by Finnemore and Hantzsche (1983) is used below to predict the long-term maximum <br /> rise of the mound: <br /> h=H +Zm =2 <br /> where: It=distance from boundary to mid-point of the long-term mound, in ft <br /> H=height of stable groundwater table above impermeable boundary, in ft <br /> Zm=long-term maximum rise of the mound, in ft <br /> Substituting known and estimated values for the variables,we find the following: <br /> H =From the attached well log for the on-site well that was drilled in 1976, a clay layer exists <br /> from 16 to 60 ft below grade. Therefore, since the water table is at 10 ft, and using 16 ft as the <br /> boundary, H= 6 ft. Long-term maximum rise is estimated at 4. Therefore, It=6+4=2= 8 <br /> Zm= IlA) (4 I n 1 Kh 10.5 ( Sy) -o.sn <br /> where:: Q=average daily flow in W/day <br /> A= area of disposal field in ft' <br /> C =mounding equation constant <br /> L =length of disposal field in ft <br /> K=horizontal permeability of soil in ft/day <br /> n=mounding equation exponent <br /> Sy= specific yield of receiving soil in percent <br /> t =time since the beginning of wastewater application in days <br /> Substituting known constants for the variables, we find the following: <br /> Q = 2500 gpd- 7.48 gals/ft' = 334 ft'/day <br /> A =3,600 ftZ <br /> C =Length to width ratio= 1,therefore, C = 3.4179 <br /> L =60ft <br /> Page -5- <br /> Chesnq Consufting <br />