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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q): 237 gals/day Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream (N,): 85.00 mg/L-N Denitrification (d): 35.0%' <br /> Site Area (A): 4.00 Acres Deep Perc. of Rain (R): 4.00 in/yr <br /> Waste Loading (W): 0.80 in/yr <br /> Result: <br /> Mass Balance(N,): 10.0 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 100% <br /> Equations: <br /> (W) in = (Q) gal x 1 ft' x 365 day x 1 acre x 12 in x 1 Find W <br /> yr day 7.48 gal 1 year 43.560 ft2 1 ft (A)acre <br /> 0.8 in/yr(site)=237ga%day x(1 cu-tt/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-It)x(12 in/1 R)x(1 site/4 acres) <br /> N.= WN...(1-d)+RNA, Hantzsche-Fennemore Equation(Nc1 <br /> W+R <br /> 10.01 mg/L-N=((0.8 in/yr x 85 mg/L-N x(1-0.35))+(4 in/yr x Img/L-N))/(0.8 in/yr+4 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration (mg/1)of combined effluent and rainfall percolate(10.01 mg/L-N). <br /> W= Uniform waste water loading for study area (in/yr) (0.8 inches/year). <br /> Nw =Total nitrate-N concentration of waste water percolate(85 mg/L-N). <br /> d = Fraction of nitrate-N loss due to denitrification in the soil (35%). <br /> R= Uniform deep percolation of rainfall (4 in/yr). <br /> Nb= Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 85 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 35%. <br /> 3. Estimated deep percolation of rainfall is 4 in/yr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> NEIL O. ANDERSON <br /> AN D ASSOCIATES <br /> E07213A <br /> Plate 2 <br />