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APPENDIX F <br /> DISSOLVED TPH-g VOLUME ASSUMPTIONS AND CALCULATIONS <br /> PAGE 7 OF 7 <br /> Multiplying M50,.,,by the hydrocarbon concentration yields the approximate mass of dissolved hydrocarbons <br /> in the saturated portion of the ellipse cylinder: <br /> M50p.,, (101,770 lbs)(0.000000525)=0.05 lbs TPH-g <br /> Dividing M50poS by the weight of one gallon of gasoline, 6.25 lbs/gallon, will yield the volume of TPH-g <br /> dissolved into the ground water of the ellipse cylinder: <br /> V50p.1=(M50 P.J/6.25lb/gal) =0.05 lbs/6.25 lbs/gal=0.008 gallons of dissolved TPH-g <br /> Combining the total volume of dissolved TPH, impacted POST-REMEDIATION ground water yields <br /> approximately 2,264 ft' containing an estimated 0.02 gallons of TPH-g, equivalent to 0.13 pounds of <br /> TPH-g. <br />