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Lodi Honda <br /> 1700 S. Cherokee Lane,Lodi, CA 95240 <br /> Waste Oil Tank Information <br /> (Normal Operation- Short) <br /> _ Wt tank full= 4886 Ibs <br /> Wt tank empty= 1086 Ibs <br /> 2.00 ft Wt Uquld= 3800 Ibs <br /> FOvertuminq wt'. Htank= 5.2917 ft <br /> 5.182 It -� 5.292 ft Governing Wtank= 4.000 ft <br /> 2.00 ft Hliqu;d 5.1823 ft <br /> 3.528 ft whaw, hOTO 3.528 ft <br /> Armt= 2.000 ft <br /> Army= 2.000 ft <br /> V Base Shear A Tank Length(long)= 4.000 ft <br /> 4.00 it Tank Width(short)=1 4.000 ft <br /> FAnchor Pull Out= 0 lbs <br /> 1. Calculate Overturning & Resisting Moments <br /> MOT=FOT(hOTM)= 3.528 xFOT <br /> MR=WttankemptyXAffnt+Wtuquid x Arml.+Fanchor X Arnie 1,086 x 2.000+3,800 x 2.000+0 x 4.000= 5,772 ft-lbs <br /> 2. Set MST=MR <br /> 3.528 FOT = 9,772 <br /> FOT= 9,772/3.528 = 2,770 Ibs <br /> 3. Calculate Lateral Seismic Force <br /> V= 0.30 X SDS X W(tank fuel)X le Base Shear(ASCE 7-10, 15.4.2) <br /> V= 0.30 x 0.597 x 4,886 x 1.25 = X24 Ibs <br /> Fx=Cvx x V and Cvx=Wx x hxK/(j W;x h;K) Lateral Seismic Force(ASCE 7-10, 12.8.3) <br /> Tapprox=Ct x hnx Fundamental Period(ASCE 7-10, 12.8.2.1) <br /> Ct= 0.02 (ASCE 7-10, Table 12.8-2) <br /> X= 0.75 (ASCE 7-10, Table 12.8-2) <br /> Tapproz Ct x hnx= 0.02 x(5.292) 0.75 = 0.070 s <0.5 s K= 1.00 <br /> Cvx=Wx x hxK/(I W;x h;K) = 4,886 x 3.528^1 /(1,086 x 3.528^1 + 3,800 x 3.528^1)= 1.00 <br /> Fx=Cvx x V= 1.00 x 1,094 = 1094 Fot> Fx <br /> Tank is Stable <br /> 4. Calculate Safety Factor <br /> SF = F,,t/Fx= 2,770/1,094= 2.53 > .5 OK-Tank is Stable <br /> 5. Calculate Resistance to Sliding � ys , � <br /> V<W tan 30°= 4,886 x tan 30° = 2821 > Base Shear of 109 <br /> y; <br /> Seismic/Anchoring Findings: The tank as designed and operated,and the containment area in o. C534 7 rn <br /> which it is located proved to be seismically sound. <br /> * <br /> P. 613 �7 <br /> CIVI- <br /> qTF CF CA1-�F�4 <br />