Laserfiche WebLink
~ Lodi Honda <br /> 1700 S. Cherokee Lane, Lodi, CA 95240 <br /> Used Coolant Tank Information <br /> (Normal Operation-Short) <br /> Wt tank tun= 2731 lbs <br /> Wt tank empty= 654 Ibs <br /> 1.38 ft Wt Liquid= 2077 Ibs <br /> Fovartuming Wt tW+e Htank= 3.2917 ft <br /> 3.208 ft � Ir- <br /> i 3,292 ft Governing Wtank= 2.750 ft <br /> 1.38 ft Hliquid 3.2083 ft <br /> 2.194 ft w�,,, hoTM= 2.194 ft <br /> Arm,= 1.375 ft <br /> t-- ArmL= 1.380 ft <br /> V Base Shear A Tank Length(long)= 4.583 ft <br /> 2.75 ft Tank Width(short)= 2.750 ft <br /> FAnchor Pun Out= 0 Ibs <br /> 1. Calculate Overturning & Resisting Moments <br /> MOT= FOT(hoTM)= 2.194 xFOT <br /> MR=Wttank empty xArml+Wtuqum x ArmL+Fanchor X A"A" 654 x 1.375+2,077 x 1.380+0 x 2.750= 3,769 ft-Ibs <br /> 2. Set M,,T= Ma <br /> 2.194 FOT = 3,769 <br /> FOT= 3,769/2.194 = 1,718 Ibs <br /> 3. Calculate Lateral Seismic Force <br /> V= 0.30 X SDS X W(tank full)X le Base Shear(ASCE 7-10, 15.4.2) <br /> V= 0.30 x 0.597 x 2,731 x 1.25 Ibs <br /> Fx=Cvx x V and Cvx=Wx x hxK I(�W,x hiK) Lateral Seismic Force(ASCE 7-10, 12.8.3) <br /> x Fundamental Period ASCE 7-10, 12.8.2.1 <br /> TePProz Ct X hn ( ) <br /> Ct= 0.02 (ASCE 7-10, Table 12.8-2) <br /> X= 0.75 (ASCE 7-10, Table 12.8-2) <br /> Tapprox=Ct X hnx= 0.02 x(3.292) 0.75 = 0.049 s < 0.5 s K= 1.00 <br /> Cvx=WX x hxK/(�Wi x hiK) = 2,731 x 2.194^1 /(654 x 2.194^1 + 2,077 x 2.194^1)= 1.00 <br /> Fx=Cvx x V= 1.00 x 611 = 611 Fot> Fx <br /> Tank is Stable <br /> 4. Calculate Safety Factor <br /> SF = Fot I Fx= 1,7181611 = 2.81 >2.5 OK-Tank is Stable <br /> 5. Calculate Resistance to Slidinq <br /> V<W tan 30° = 2,731 x tan 30° = 1577 > Base Shear of 611 <br /> Seismic/Anchoring Findings: The tank as designed and operated,and the containment area in <br /> which it is located proved to be seismically sound. 34 7 rnn <br /> P. W3 -7 <br /> 7 <br /> F <br /> OF C � - <br />