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Secondary Containment Installation Instructions <br /> .�,n.�"����`���ka, '�3�, ,� 3,z,,air,�.���`ifs'y„�„�;�;��ts �� �`���': �3,^��;�� �, .� � `�,a�•�.�:„,'��.�<a� ':. �',�����3��"d' .�.,,},.���?,x,�.�.,k` �.�..,,,.ia �,�=..�„. <br /> Exposed.Product <br /> P <br /> Pi 9 <br /> rl <br /> Machined Ends <br /> Figure 5 Figure 6 <br /> NOTE: Coupling placement must be planned when bonding the primary system. This results in <br /> before positioning of containment pipe, be- additional insertion length ("make up") when <br /> cause the pipe must have scarfed ends. bonding the joints. Make allowances for the <br /> Additional consideration may be necessary for "make up" length when calculating the length of <br /> various types of leak detection systems. the containment pipe. The calculation procedure <br /> is as follows: <br /> C. Calculating Lengths for Containment <br /> Piping-To determine the length of the contain- a. Determine the distance from the edges of the <br /> ment piping,you must first dry fit the primary containment fittings. <br /> joints. Make sure that the tapered primaryjoints <br /> are fit tightly together, and place the bottom half b. Add the minimum bond lengths for both con- <br /> of the containment fittings under the primary fit- tainment joints (shown in Table 3). This will <br /> tings. provide pipe for insertion into the sockets of <br /> the containment fittings. <br /> Use a tape measure to determine the distance <br /> from the edge of the two containment halves c. Subtract the "make up" dimensions for the pri- <br /> placed under the primary fittings. Check Table 3 maty joints (from Section 10 of Manual No. <br /> to determine the insertion depth of the contain- F6000). This will allow for the decrease in <br /> ment pipe (minimum bond length). overall length of the primary piping when as- <br /> sembled. <br /> Refer to Section 10 on Close Tolerance Piping in <br /> Manual No. F6000 to determine the "make up” di- In equation form: <br /> mension for the primary piping. The adhesive <br /> acts as a lubricant during insertion of the spigot Lp=X+ 2LB-2M <br /> Table 3 Minimum Bond Lengths for Where: <br /> Secondary Containment Fittings Lp = Containment pipe length, ft. <br /> X = Distance from edge of one contain- <br /> Containment Minimum Bond ment fitting to the edge of the next <br /> Size Length (LB) containment fitting <br /> (in.) (in.) LB = Minimum bond length for <br /> 3 '23/4 containment joints <br /> 4 214 M = Make up dimension for primary <br /> 6 23/4 joints from Manual No. F6000 <br /> 8 3 <br /> 10 4 Sample problem: <br /> 12 41h <br /> 14 41h Given: 16"containment pipe over 14"primary <br /> 16 41k pipe. When laid out, the distance from the edges <br /> of the containment fittings is 12' 3". <br /> 5 <br />