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&I Design Example Solution (Cont) ! <br />2(Tan2g0)+ l(Tan32°)+.5(Tan32° ) <br />= Tan -1 3.5 j = 29.7° <br />Waste Friction Angle 02 = 250 <br />Surcharge q = 0 <br />Radius of Depression r, = 3 ft. <br />Multiaxial Rupture Strain of Liner T R = 10% <br />Factor of Safety FS = 2 <br />Design Life Life = 100 years <br />Simi <br />B,=2(3ft.)=6ft. <br />Hcl =1.0 (from figure 2) <br />Bt <br />Step 2 <br />Hct =6ft. (1.0)=6ft. <br />®t =Tan-1(3f).l6ft.)=26.60 <br />• <br />r� <br />u <br />