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Mass-Volume Calculation of Dissolved MTBE - 04 Jane to 02 July 2001 <br /> FLAG CITY CHEVRON- 6421 Capitol Avenue,Lodi, CA <br /> Assumptions <br />' • A total volume of 747,592 gallons was extracted from wells EW-2, EW-4, EW-5, EW-6, <br /> EW-7,EW-8,EW-9 and EW-10 between 04 June 2001 and 02 July 2001 (based on effluent <br />' flow meter observations between 04 June and 02 July 2001) <br /> • Data collected from the pump and treat influent and extraction well-head grab ground water <br /> samples were representative of general extracted ground water conditions <br /> One cubic foot of water contains 7 48 gallons; conversely, one gallon of water is equivalent to <br />' 0 1337 cubic feet, so the volume of processed water is given by <br /> V= (747,592 gallons)(0 1337 ft3/gal) = 99,953 fe processed water <br />' One gallon of water weighs 8 337 lbs /gal at 60'F, so the mass of processed water is given by <br />' Mwaf,,,= (747,592 gallons)(8 337 lbs/gal) = 6,232,675 lbs. processed water <br /> Multiplying the mass of the processed water by the average MTBE concentration(06-04-01=4 tyg/L <br /> and 07-02-01 = 28 kcglf-, avg = 35 ,ug[L) yields the approximate mass of MTBE removed from <br /> processed water <br /> MMTBE = (6,232,675 lbs)(0 000000035) =0.22 lbs MTBE <br /> A converstion factor of 0 4536 kg/lb can be used to convert pounds of MTBE to kilograms of <br /> MTBE <br /> MMTOE= 0 66 lbs MTBE (0 4536 kg/lb) 100 g of MTBE <br />' Advanced GeeEnwronmental,Inc- <br />, <br />