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' Mass-Volume Calculation of Dissolved MTBE - Second Quarter 2001 <br />' FLAG CITY CHEVRON- 6421 Capitol Avenue, Lodi, CA <br /> Assumptions <br />! • A total volume of 2,395,645 gallons was extracted from wells EW-2, EW-4, EW-5, EW-6, <br /> EW-7,EW-8,EW-9 and EW-10 between 09 April 2001 and 02 July 2001 (based on effluent <br />' flow meter observations between 09 April and 02 July 2001) <br /> • Data collected from the pump and treat influent and extraction well-head grab ground water <br /> samples were representative of general extracted ground water conditions <br /> One cubic foot of water contains 7 48 gallons, conversely, one gallon of water is equivalent to <br />' 0 1337 cubic feet, so the volume of processed water is given by <br /> V= (2,395,645 gallons)(0 1337 Wlgal) =320,298 ftp processed water <br />' One gallon of water weighs 8 337 lbs/gal at 60°F, so the mass of processed water is given by <br />' Mwater=(2,395,645 gallons)(8 337 lbs/gal)= 19,972,492 lbs. processed water <br /> Multiplying the mass of the processed water by the average MTBE concentration (04-09-01= <br /> 1004g/L, 05-03-01= 140,ug/L, 06-04-01=41yg/L and 07-02-01 = 28 �zg(L, avg = 77 ,ug/L) yields <br /> the approximate mass of MTBE removed from processed water <br /> MSE= (19,972,492 lbs)(0 000000077) = 1.54 lbs MTBE <br /> A converstion factor of 0 4536 kg/lb can be used to convert pounds of MTBE to kilograms of <br /> MTBE <br /> MSE= 154 lbs MTBE (0 4536 kg/lb) =699 g of MTBE <br /> i <br /> 1 <br /> .advanced GeoEnvironmentat,Inc <br />