Laserfiche WebLink
Mass-Volume Calculation of Dissolved MTBE - 03 January 2002 to 04 February 2002 <br /> ` FLAG CITY CHEVRON - 6421 Capitol Avenue, Lodi, CA <br /> Assumptions <br /> • A total volume of 842,673 gallons was extracted from wells EW-4,EW-5, EW-9 and EW-10 <br /> between 03 January and 04 February 2002 (based on effluent flow meter observations) <br /> • Data collected from the pump and treat Influent and extraction well-head grab ground water <br /> samples were representative of general extracted ground water conditions <br /> One cubic foot of water contains 7 48 gallons, conversely, one gallon of water is equivalent to <br /> 0 1337 cubic feet, so the volume of processed water Is given by <br /> V=(842,673 gallons)(0 1337 fl/gal) = 112,665 fe processed water <br /> One gallon of water weighs 8 337 lbs/gal at 60°F, so the mass of processed water is given by <br /> MI.te,= (842,673 gallons)(8 337 lbs /gal) = 7,025,365 lbs. processed water <br /> Multiplying the mass of the processed water by the average MTBE concentration(01-03-02=41µg/L <br /> and 02-04-02 = 29 4g/L, avg = 35 µg/L) yields the approximate mass of MTBE removed from <br /> processed water <br /> MMMT=(7,025,355 lbs)(0 000000035) =0.25 lbs MTBE <br /> A converstion factor of 0 4536 kg/lb can be used to convert pounds of MTBE to grams of MTBE <br /> MMTaz = 0 25 lbs MTBE (0 4536 kg/lb) = 112 g of MTBE <br /> Advanced CeoEnviroomental,Inc. <br />