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{ Mass-Volume Calculation of Dissolved MTBE - 04 February 2002 to 27 March 2002 <br /> FLAG CITY CHEVRON- 6421 Capitol Avenue, Lodi, CA <br /> Assumptions <br /> • A total volume of 2,211,908 gallons was extracted from wells EW-4, EW-5, EW-9 and <br /> EW-10 between 04 February and 27 March 2002 (based on effluent flow meter <br /> observations) <br /> • Data collected from the pump and treat Influent and extraction well-head grab ground water <br /> samples were representative of general extracted ground water conditions <br /> One cubic foot of water contains 7 48 gallons, conversely, one gallon of water is equivalent to <br /> 0 1337 cubic feet, so the volume of processed water Is given by <br /> V= (2,211,908 gallons)(0 1337 ft/gal) =295,732 fe processed water <br /> One gallon of water weighs 8 337 lbs/gal at 60'F, so the mass of processed water Is given by <br /> M,v,,,,= (2,211,908 gallons)(8 337 lbs/gal) = 18,440,677 lbs. processed water <br /> Multiplying the mass of the processed water by the average MTBE concentration(02-0402=29µg/1, <br /> 03-27-02 = 12 µg/l, avg = 20 5 µg/1) yields the approximate mass of MTBE removed from <br /> processed water <br /> MMTBE _ (18,440,677 lbs)(0 0000000205) = 0.37 lbs MTBE <br /> A converstion factor of 0 4536 kg/lb can be used to convert pounds of MTBE to grams of MTBE <br /> MMTBE= 0 37 lbs MTBE (0 4536 kg/lb) = 168 g of MTBE <br /> Admneed GeoEnvironnnental,Inc <br />