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ARCHIVED REPORTS XR0001527
Environmental Health - Public
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EHD Program Facility Records by Street Name
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3500 - Local Oversight Program
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PR0544465
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ARCHIVED REPORTS XR0001527
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Last modified
5/16/2019 1:30:52 PM
Creation date
5/16/2019 1:08:43 PM
Metadata
Fields
Template:
EHD - Public
ProgramCode
3500 - Local Oversight Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0001527
RECORD_ID
PR0544465
PE
3528
FACILITY_ID
FA0005837
FACILITY_NAME
STEFANOS GASOLINE*
STREET_NUMBER
1419
Direction
E
STREET_NAME
CHARTER
STREET_TYPE
WAY
City
STOCKTON
Zip
95205
APN
15137016
CURRENT_STATUS
02
SITE_LOCATION
1419 E CHARTER WAY
P_LOCATION
01
P_DISTRICT
001
QC Status
Approved
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EHD - Public
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' MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br />' Assumptions <br /> • Utilizing analytical data collected from au-samples(Table 4)and from field measurements collected during the <br />' SVE remediation(Table 2),the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> M=C• Q• t <br /> where M—cumulative mass recovered(kg) <br />' C=vapor concentration(kg/m3) <br /> Q=extraction flow rate(m3/hr) <br /> t=operational period(hrs) <br />' The average inlet TPH-g concentration and average inlet flow <br /> rates during each time interval were utilized for calculating <br /> the approximate mass/volume of extracted gasolme hydrocarbons <br /> 02 to 17 November 2004 <br />' 1) The average analytical TPH-g concentration for this time interval was determined to be 7,750µg/l(11/02/04= <br /> 14,000 gg/l and 11/17104=650,avg =7,750 pg/1) The average flow rate was calculated at 5 2 inches of water <br /> or approximately 125 cubic feet per mmute(nomograph),the operational period was equal to 356 7 hours of <br /> running tune(Table 6) <br /> C 7,750 pg/1=0 007750 kg/m' 00 b 7s <br /> Q 5 2 inches water 125 f13 <br /> /min Jho `3 <br /> t=356 7 hours <br />' Converting Q to M3/hour yields <br /> Q=(125 fi3/min) •(60 mm/hour)•(0 0283168 m3/f13)=212 38 m'/hour <br /> M=C• Q•t=(0 007750 kg/m') •(212 38 M3/hour)• (356 7 hours)=587 12 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br />' 587 12 kg of gas•2 2046 lbs of gas/kg of gas= 1,294 34 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 1,294 34 lbs of gas • 0 16 gal of gas/lbs of gas 207.09 gallons of gasoline <br /> I <br /> I <br />
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