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MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br />' Assumptions <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br />' SVE remediation(Table 2),the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br />' M=C • Q•t <br /> where M=cumulative mass recovered(kg) <br />' C=vapor concentration(kg/m') <br /> Q=extraction flow rate(m'/hr) <br /> t_operational period(hrs) <br />' The average mlet TPH-g concentration and average mlet flow rates during each <br /> tune interval were utilized for calculating <br /> the approximate mass/volume of extracted gasoline hydrocarbons <br /> 17 November to 22 December 2004 <br />' 1) The average analytical TPH-g concentration for this time interval was determined to be 1,100µg/l(11117/04= <br /> 14,000 µg11 and 12/22/04=700,avg = 1,100µg/1) The average flow rate was calculated at 6 3 inches of water <br /> • or approximately 140 cubic feet per minute(nomograph),the operational period was equal to 779 3 hours of <br /> running time(Table 6) <br /> C 1,100 µg11=0 00 1 100 kg/m3 <br /> Q 6 3 inches water 140 ft Imm <br /> t=779 3 hours <br />' Converting Q to m'/hour yields <br /> Q=(140 ft'/mm)•(60 mm/hour)•(0 0283168 m'Ife)=237 86 m3/hour <br />' M=C • Q •t=(0 001100 kg/m')•(237 86 m'/hour)• (779 3 hours)=203 90 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br />' 203 90 kg of gas•2 2046 lbs of gas/kg of gas=449 52 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields - <br /> 449 52 lbs of gas • 0 16 gal of gas/lbs of gas 71.92 gallons of gasoline <br /> r <br /> I <br />