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' MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> • <br />' Assumptions <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br />' SVE remediation(Table 2),the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br />' M=C - Q -t <br /> where M=cumulative mass recovered(kg) <br />' C=vapor concentration(kg/m3) <br /> Q=extraction flow rate (m'/hr) <br /> t=operational period(hrs) <br />' The average mlet TPH-g concentration and avera a mlet flow <br /> rates during each tune interval were utilized for calculating <br /> the approximate mass/volume of extracted gasoline hydrocarbons <br /> 26 April to 09 May 2005 <br />' 1) The average analytical TPH-g concentration for this tune interval was determined to be 110 pg/1(04116105= <br /> 0 gg/l and 05/09/05=220, avg =110 µg/1) The average flow rate was calculated at 6 3 inches of water or <br /> approximately 140 cubic feet per minute (nomograph), the operational period was equal to 307 8 hours of <br /> running time(Table 6) <br /> C l 10 µg/1=0 000110 kg/m' <br /> Q 6 3 mches water 140 fl/rnm <br /> t=307 8 hours <br /> Converting Q to M3/hour yields <br /> Q (140 ft/mm)-(60 nun/hour)-(0 0283168 m'/ft)=237 86 m3/hour <br /> M=C - Q- t=(0 000110 kg/m') •(237 86 m'/hour)-(307 8 hours)= 8 05 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 8 05 kg of gas• 2 2046 lbs of gas/kg of gas= 17 75 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 17 75 lbs of gas • 0 16 gal of gas/lbs of gas 2 84 gallons of gasoline <br /> I � <br /> I <br />