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' MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br />' Assumptions <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br />' SVE remediation(Table 2),the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br />' M=C • Q • t <br /> where M—cumulative mass recovered(kg) <br />' C=vapor concentration(kg/m') <br /> Q=extraction flow rate(m'/hr) <br /> t=operational period(hrs) <br />' The average mlet TPH-g concentration and average inlet flow rates during each time interval were utilized for calculating <br /> the approximate mass/volume of extracted gasoline hydrocarbons <br /> 08 March to 26 April 2005 <br />' 1) The average analytical TPH-g concentration for this time interval was determined to be 350 µg11(03/08/05= <br /> 700 µg11 and 04/26105=0, avg =350 µg11) The average flow rate was calculated at 6 3 inches of water or <br /> approximately 140 cubic feet per minute(nomograph),the operational period was equal to 700 hours ofrunnmg <br /> time(Table 6) <br /> C 350 µg/1=0 000350 kg/m3 <br /> Q 6 3 inches water 140 ft3/mm <br /> t=700 hours <br /> Converting Q to m3/hour yields <br /> Q=(140 ft3/mm)•(60 mm/hour)•(0 0283168 m3/ft')=237 86 m'/hour <br />' M—C• Q•t=(0 000350 kg/m') •(237 86 m'/hour)•(700 hours)=58 28 kg of gasoline <br /> Converting kg of gasolme to pounds of gasoline yields <br />' 58 28 kg of gas • 2 2046 lbs of gas/kg of gas= 128 48 lbs of gasolme <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 122 29 lbs of gas • 0 16 gal of gas/lbs of gas 20 55 gallons of gasoline <br /> 1 <br /> 1 <br /> 1 <br />