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Nitrate Ma s_Balance_ Calculation <br /> Parcel <br /> Data Input: <br /> Effluent Quantity(Q): 490 gals/day Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream (N,): 40.00 mg/L-N Denitrification (d): 35.0% <br /> Site Area (A): 2.50 Acres Deep Perc. of Rain (R): 5.76 in/yr <br /> Result: <br /> Mass Balance - <br /> 8 mg/L-N <br /> MCL Drinking Water Nitrate a N: 10.0 mg/L-N Waste Loading (W): 2.63 in/yr <br /> Percent of MCL Nitrate as N IX <br /> Equations: <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find <br /> yr day 7.48 gal 1 year 43,560 ft' 1 ft (A) acre <br /> 2.63 in/yr(site) =490 gal/day x(1 cu-ft/7.48 gals)x (365 days/1 year)x (1 acre 143,560 sq-ft)x(12 in/1 ft)x (1 site 12.5 acres) <br /> N,= WNw(1-d)+RN,, Hantzsche-Fennemore Equation(Nd <br /> W+R <br /> 8.85 mg/L-N= ((2.63 in/yr x 40 mg/L-N x (1-0.35))+(5.76 in/yr x 1 mg/L-N))/(2.63 in/yr+5.76 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration (mg/1) of combined effluent and rainfall percolate (8.85 mg/L-N). <br /> W= Uniform waste water loading for study area (in/yr) (2.63 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate (40 mg/L-N). <br /> d = Fraction of nitrate-N loss due to denitrification in the soil (35%). <br /> R = Uniform deep percolation of rainfall (5.76 in/yr). <br /> Nb= Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 40 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 35%. <br /> 3. Estimated deep percolation of rainfall is 5.76 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> "44 NEIL O. ANDERSON <br /> A N D A 5 5 0 C I A T E 5 <br /> Plate 12 <br />