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Calculated dissolved benzene concentrations-present in-MW-11=and --- - <br /> MW-13 . <br /> The following equation provides an estimate of the maximum <br /> dissolved benzene concentration expected in downgradient wells MW- <br /> 11 and -13. <br /> K = 2 . 303/t log(a/a-x) <br /> where: a = 10, 000 ppb - MW-4, April 13 , 1989 <br /> a-x = calculated reduced concentration in MW-11 and <br /> MW-13 <br /> t = d/v = 75 ft/0. 02 ft/day = 3750 days <br /> K = 0. 001 days-1 <br /> a-x = calculated maximum benzene concentration = 229 ppb, after a <br /> migration time of 3750 days <br /> With the exception of the July 1993 groundwater analytical data, <br /> all previous samples collected from MW-11 contained dissolved <br /> benzene concentrations in excess of the estimated concentration of <br /> 229 ppb. Concentration values from May 1992 , July 1992 and October <br /> 1992 were 1500 ppb, 620 ppb and 1300 ppb, respectively. The <br /> possibility exists that the elevated dissolved BTEX concentrations <br /> observed in MW-11 may in part be derived from a secondary source <br /> area (eg. the smaller product tanks removed in 1984) . Further <br /> analyses to determine the possibility of a secondary hydrocarbon <br /> source is 3ustif ied. <br /> MW-13 has only been sampled during the July 23 , 1993 monitoring <br /> event . The July 1993 sample contained total <br /> toluene/ethylbenzene/xylene concentrations less than 10 ppb, no <br /> detectable benzene, and a TPH-G value of 730 ppb. Due to the 15 <br /> foot recorded decline in local depth to groundwater, it is possible <br /> that the dissolved BTEX concentrations represented in the July 1993 <br /> sampling event do not represent the- maximum values which have <br /> migrated, or will migrate, through the groundwater sampled by MW- <br /> 13 . <br /> 5) Estimated 10 ppb benzene concentration distance from MW-11, at <br /> time "t". <br /> The following estimation assumes the same dissolved benzene <br /> degradation/attenuation rate calculated for MW-3 , MW-4 and MW-5, <br /> above. <br /> (a) K = (2 . 303/t) log(a/a-x) <br /> 5 <br />