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VOLUME-MASS CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br />' Assumptions <br /> • Utilizing analytical data collected from au samples(Table 4)and from field measurements collected during the <br />' SVE pilot test (Table 5), the volume and mass of extracted gasoline hydrocarbons at the site can be <br /> approximated <br />' The hydrocarbon volume-mass removed during the operating period can be calculated using the following equation <br /> M=C• Q•t <br />' where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m') <br />' Q=extraction flow rate (m'/hr) <br /> t=operational period(hrs) <br />' The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating the <br /> approximate mass/volume of extracted gasoline hydrocarbons <br /> t22 December 2004 to 16 March 2005 <br /> 1) The average analytical TPH-g concentration for this time interval was determined to be 278 µg/l(12-22-04= <br />' 320 µg/1,01-20-05=320µg/1,02-16-05=ND&03-16-05=420 µg/1,avg =278 µg/1) The average flow rate <br /> was calculated at 2 7 inches of water or approximately 84 cubic feet per mmute(nomograph),the operational <br /> period was equal to 2,016 hours of running time(Table 6) <br />' C z 278 µg/1=0 000278 kg/m' <br /> Q z 2 7 inches water z 84 ft/mm <br />' t=2,011 hours <br /> Converting Q to m'/hour yields <br />' Q=(84 fl3/min)•(60 mm/hour)-(0 0283168m3/ft3)= 142 7 m3/hour <br /> M=C- Q•t=(0 000278 kg/m') •(142 7 m'/hour)• (2,016 hours)=79 98 kg of gasoline <br />' Converting kg of gasoline to pounds of gasoline yields <br /> 79 98 kg of gas • 2 2046 Is of gas/kg of gas= 176 3 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br />' 176 3 lbs of gas • 0 16 gal of gas/lbs of gas 28 2 gallons of gasoline <br />' Advanced GeoEnvironmental,Inc <br /> 1 <br />