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VOLUME-MASS CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br />' Assumptions <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br />' SVE pilot test (Table 5), the volume and mass of extracted gasoline hydrocarbons at the site can be <br /> approximated <br /> The hydrocarbon volume-mass removed during the operating period can be calculated using the following equation <br /> M=C• Q• t <br />' where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m) <br />' Q=extraction flow rate(m'/hr) <br /> t=operational period(hrs) <br />' The average inlet TPH-g concentration and average flow rates during each tune interval were utilized for calculating the <br /> approximate mass/volume of extracted gasoline hydrocarbons <br /> 16 March 2005 to 08 June 2005 <br /> 1) The average analytical TPH-g concentration for this time interval was determined to be 220 µg/l(03-16-05� <br />' 420µg/1,04-06-05=300µg/l,05-03-05= 110&06-08-05=ND µg11,avg =220 µg/1) The average flow rate <br /> was calculated at 13 inches of water or approximately 54 cubic feet per minute(nomograph),the operational <br /> period was equal to 2,016 hours of running tune(Table 6) <br />' C = 220 µg/1=0 000220 kg/m' <br /> Q = 13 Inches water= 54 ft3/mm <br />' t=2,016 hours <br /> Converting Q to m'/hour yields <br /> Q=(54$/min)•(60 mm/hour)•(0 0283168m3/ft)=91 75 m'/hour <br /> M=C•Q •t=(0 000220 kg&)•(91 75 m3/hour) • (2,016 hours)=40 7 kg of gasoline <br />' Converting kg of gasoline to pounds of gasoline yields <br /> 40 7 kg of gas • 2 2046 lbs of gas/kg of gas=89 71 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 89 71 lbs of gas • 0 16 gal of gas/lbs of gas ;z� 14 35 gallons of gasoline <br />' Advanced GeoEnvironmental,Inc <br />