Laserfiche WebLink
n d• � <br /> VOLUME-MASS CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> Assumptions <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br /> SVE pilot test (Table 5), the volume and mass of extracted gasoline hydrocarbons at the site can be <br /> approximated <br /> The hydrocarbon volume-mass removed during the operating period can be calculated using the following equation <br /> M=C• Q • t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m') <br /> Q=extraction flow rate(m/hr) <br /> t=operational period(hrs) <br /> The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating the <br /> approximate mass/volume of extracted gasoline hydrocarbons <br /> 20 March 2003 to 23 June 2003 <br /> 1) The average analytical TPH-g concentration for this time interval was determined to be144 µg11(04-16-03— <br /> 190µg11,05-15-03=41 µg11,06-23-03=200µg/1,avg = 144µg11) The average flow rate was calculated at 4 2 <br /> inches of water or approximately 105 cubic feet per minute(nomograph),the operational period was equal to <br /> 1,767 hours of running time(Table 6) <br /> C z 144 µg11=0 000144 kg/m' <br /> Q z 4 2 inches water z 105 ft3/min <br /> t= 1,767 hours <br /> Converting Q to m'/hour yields <br /> Q=(105 ft'/min)•(60 nun/hour) •(0 0283168d/ft3)= 178 4 m'/hour <br /> M=C• Q • t=(0 000144 kg/m') •(178 4 m'/hour) • (1,767 hours)=45 4 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 45 4 kg of gas• 2 2046 lbs of gas/kg of gas=100 1 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 100 1 lbs of gas • 0 16 gal of gas/lbs of gas r 16 gallons of gasoline <br />