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MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> Assumptions <br /> Utilizing analytical data collected from au samples(Table 4)and from field measurements collected during the <br /> SVE pilot test(Table 5),the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> M=C• Q • t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m') <br /> Q=extraction flow rate(m3/hr) <br /> t=operational period(hrs) <br /> The average utlet TPH- concentration and average flow rates during each time interval were utilized for calculating the <br /> g g g g g <br /> approximate mass/volume of extracted gasoline hydrocarbons <br /> 17 December 2002 to 20 March 2003 <br /> 1) The average analytical TPH-g concentration for this time interval was determined to be 307 pg/l g/l(12-17-03= <br /> 530 pg/1,01-17-03=270 pg/1,02-17-02=120 pg/l,avg =307µg/1) The average flow rate was calculated at 4 4 <br /> inches of water or approximately 110 cubic feet per minute(nomograph),the operational period was equal to <br /> 2,132 hours of running time(Table 6) <br /> C = 307 µg/1=0 000307 kghr 3 <br /> Q z 4 4 inches water = 110 fie/min <br /> t=2,132 hours <br /> Converting Q to m'/hour yields <br /> Q=(110 ft/nun) -(60 mm/hour) •(0 0283168rn/ft)= 186 9 ml/hour <br /> IM=C • Q• t=(0 000307 kg/m') •(186 9 mg/hour) • (2,132 hours)= 122 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 122 kg of gas• 2 2046 lbs of gas/kg of gas=269 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 269 lbs of gas • 0 16 gal of gas/lbs of gas = 43 gallons of gasoline <br /> I <br /> I <br />