Laserfiche WebLink
29 May 2020 11.rt ancedGe0 <br /> Project No. 20-6014 e Owned Company <br /> Page 12 of 14 <br /> RESIDENTIAL: <br /> The Hantzsche / Finnemore (Nr) equation for residential home application.- <br /> Nr = I x Nw (1-d) + R x Nb . (I+R) <br /> pplication:Nr = IxNw (1-d) + RxNb = (I+R) <br /> Definitions: <br /> Nr = The average concentration of nitrate-nitrogen in the recharged wastewater parts per <br /> million of nitrate-nitrogen. <br /> I = Volume rate of wastewater entering the soil averaged over the gross developed area <br /> (acres) in inches per year. The total wastewater volume for proposed project will be <br /> 150 gpd (proposed system) x 365 days of proposed operation = 150 x 365 days _ 7.48 <br /> gallons per cubic foot = 7,319 cubic feet of wastewater. Does not account for <br /> evapotranspiration likely to occur. <br /> NW = Total nitrogen concentration of wastewater at 45 mg/L-N based on the average <br /> discharge. Accounting for the loss of mg/L-N in the septic tank at 15% = 45-15%= 38.25 <br /> and the loss from the biomat at 10% 38.25 - 10% = 34.425 mg/L-N. <br /> d = Fraction of nitrogen concentration removed from the wastewater due to denitrification <br /> within the soil (25 percent for silty sandy soils). <br /> R = Estimated Deep percolation / average rainfall recharge rate per year: 3.69 inches. <br /> Nb = Background nitrate-nitrogen concentration of rainfall recharge: 1.0 mg/l. The Nb is <br /> an average value determined for San Joaquin County by the EHD. <br /> PROPOSED HOME CALCULATIONS: <br /> Nr = IxNw (1-d)+ RxNb _ (I+R) <br /> Assumptions: <br /> I = 54,750 gallons = 7,319 cubic feet wastewater - [(0.228 acres x 43,560 fee t2) _ 12 <br /> inches] = 8.84 inches/year <br /> NW = 34.425 mg/L-N <br /> d = 25 percent denitrification <br /> R = 3.69 inches/year <br /> Nb = 1.0 milligram per liter <br /> Nr = [8.84 inches/year x 34.425 mg/L-N (1-0.25)] + (3.69 inches/year x 1.0 milligram per <br /> liter) _ (8.84 inches/year + 3.69 inches/year) <br /> Nr = 231.92 _ 12.53 = 18.50 <br /> Nr = 18.50 ppm nitrogen (NO3_N) <br />