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Appendix E - Ground Water P&T Volume-Mass Calculations <br /> AGE-NC Project Nol 95-0130 <br /> Page 2 of 3 <br /> 2) 22 October 2012 - 26 November 2012 <br /> Assumptions: <br /> • A total volume of 61,650 gallons was extracted from wells EW-1, VW-2A and <br /> VW-3A between 22 October and 26 November 2012 (based on effluent flow meter <br /> observations). <br /> • Data collected from the pump and treat influent were representative of general <br /> extracted groundwater conditions. <br /> One gallon of water is equivalent to 3.79 liters, so the volume of processed water is given <br /> by: <br /> V= (61,650 gallons)(3.79 //gal) = 233,654 /processed water <br /> Multiplying the volume of the processed water by the average of the October and <br /> November 2012 TPH-g concentrations (10/12= 11000 pg/I, 11/12 = 26000 pg/l; avg.= <br /> 18,500 pg/1) yields the approximate mass of TPH-g removed from processed water: <br /> MTPH_9 = (233,654 /)(0.000018500 kg//) = 4.32 kg TPH-g <br /> A converstion factor of 2.205 Ib/kg. can be used to convert kilograms of TPH-g to pounds <br /> of TPH-g: <br /> MTPH-B = (4.32 kg TPH-g)(2.205 Ib/kg) = 9.53 lbs. TPH-g <br /> Advanced GeoEnvironmental,Inc. <br />