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Appendix E - Ground Water P&T Volume-Mass Calculations <br /> AGE-NC Project Nol 95-0130 <br /> Page 3 of 3 <br /> 3) 26 November 2012 - 18 December 2012 <br /> Assumptions: <br /> • A total volume of 35,580 gallons was extracted from wells EW-1 , VW-2A and <br /> VW-3A between 26 November and 18 December 2012 (based on effluent flow <br /> meter observations). <br /> • Data collected from the pump and treat influent were representative of general <br /> extracted groundwater conditions. <br /> One gallon of water is equivalent to 3.79 liters, so the volume of processed water is given <br /> by: <br /> V= (35,580 gallons)(3.79 //gal) = 134,848 / processed water <br /> Multiplying the volume of the processed water by the average of the November and the <br /> December 2012 TPH-g concentrations (11/12= 26,000 pg/l, 12/12 = 50,000 pg/l; avg.= <br /> 38,000 pg/1) yields the approximate mass of TPH-g removed from processed water: <br /> MTP„-9 = (134,848 /)(0.000038 kg//) = 5.12 kg TPH-g <br /> A conversion factor of 2.205 Ib/kg. can be used to convert kilograms of TPH-g to pounds <br /> of TPH-g: <br /> MTP„-g= (5.12 kg TPH-g)(2.205 Ib/kg) = 11.3 lbs. TPH-g <br /> t/ <br /> Advanced GeoFnvironmental,Inc. <br />