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Appendix E - Ground Water P&T Volume-Mass Calculations <br /> AGE-NC Project Nol 95-0130 <br /> Page 3 of 3 <br /> 3) 23 May 2013 - 17 June 2013 <br /> Assumptions: <br /> • A total volume of 55,820 gallons was extracted from wells EW-1, VW-2A and <br /> VW-3A between 23 May and 17 June 2013 (based on effluent flow meter <br /> observations). <br /> • Data collected from the pump and treat influent were representative of general <br /> extracted groundwater conditions. <br /> One gallon of water is equivalent to 3.79 liters, so the volume of processed water is given <br /> by: <br /> V= (55,820 gallons)(3.79 //gal) = 211,558 1 processed water <br /> Multiplying the volume of the processed water by the average of the May and the June <br /> 2013 TPH-g concentrations (05/13= 30,000 pg/I, 06/13 = 36,000 pg/I; avg.= 33,000 pg/1) <br /> yields the approximate mass of TPH-g removed from processed water: <br /> MTP„-9 = (211,558 1)(0.000033 kg//) = 6.98 kg TPH-g <br /> A conversion factor of 2.205 Ib/kg. can be used to convert kilograms of TPH-g to pounds <br /> of TPH-g: <br /> MTPH-g = (6.98 kg TPH-g)(2.205 Ib/kg) = 15.4 lbs. TPH-g <br /> Advanced GeoEnvironmental,Inc. <br />