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Appendix E - Ground Water P&T Volume-Mass Calculations <br /> AGE-NC Project No[ 95-0130 <br /> Page 2 of 3 <br /> 2) 23 April 2013 - 23 May 2013 <br /> Assumptions: <br /> • A total volume of 57,550 gallons was extracted from wells EW-1, VW-2A and <br /> VW-3A between 23 April 2013 and 23 May 2013 (based on effluent flow meter <br /> observations). <br /> • Data collected from the pump and treat influent were representative of general <br /> extracted groundwater conditions. <br /> One gallon of water is equivalent to 3.79 liters, so the volume of processed water is given <br /> by: <br /> V= (57,550 gallons)(3.79 //gal) = 218,115 / processed water <br /> Multiplying the volume of the processed water by the average of the April and May 2013 <br /> TPH-g concentrations (04/13= 8,000 pg/I, 05/13 = 30,000 pg/1; avg.= 19,000 pg/1) yields <br /> the approximate mass of TPH-g removed from processed water: <br /> MTPHy = (218,115 /)(0.000019000 kg//) = 4.14 kg TPH-g <br /> A converstion factor of 2.205 Ib/kg. can be used to convert kilograms of TPH-g to pounds <br /> of TPH-g: <br /> MTP„-g= (4.14 kg TPH-8)(2.205 Ib/kg) = 9.14 lbs. TPH-g <br /> Advanced CeoEnvironmental,Inc. <br />