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ARCHIVED REPORTS_XR0011931
Environmental Health - Public
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EHD Program Facility Records by Street Name
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W
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WILSON
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101
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2900 - Site Mitigation Program
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PR0541653
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ARCHIVED REPORTS_XR0011931
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Last modified
10/10/2020 10:48:20 PM
Creation date
7/9/2020 8:21:06 AM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2900 - Site Mitigation Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0011931
RECORD_ID
PR0541653
PE
2965
FACILITY_ID
FA0023871
FACILITY_NAME
TOP FILLING STATION
STREET_NUMBER
101
Direction
S
STREET_NAME
WILSON
STREET_TYPE
WAY
City
STOCKTON
Zip
95205
APN
15125307
CURRENT_STATUS
01
SITE_LOCATION
101 S WILSON WAY
P_LOCATION
01
QC Status
Approved
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EHD - Public
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t <br /> APPENDIX G <br />' SOIL VAPOR EXTRACTED VOLUME-MASS CALCULATIONS <br /> TOP FILLING STATION <br /> 101 South Wilson Way, Stockton, California <br /> Assumptions <br /> • Utilizing field measurements and analytical data collected from air samples between 07 <br /> September 2005 and 07 December 2005, the volume and mass of extracted gasoline <br />' hydrocarbons at the site can be approximated <br /> The hydrocarbon volume-mass removed during the operating period can be calculated using the <br /> following equation <br />' M= C • Q • t <br /> where M=cumulative mass recovered (kg) <br />' C =vapor concentration (kg/m') <br /> Q = extraction flow rate (m3/hr) <br /> t= operational period(hrs) <br /> 1 <br /> 1) 07 September 2005- 10 October 2005 <br />' The average analytical TPH-g concentration for this time interval was determined to be 1,150 µg/1 <br /> (09-07-05= 1,700 µg/l and 10-10-05 = 600 gg/l, avg = 1,150 µg/1) The average flow rate was <br />' calculated at 4 3 inches of water or approximately 114 cubic feet per minute (nomograph), the <br /> operational period was equal to 794 hours of running time (Table 6) <br />' TPH-g(total petroleum hydrocarbons quantified as gasoline) <br /> C z 1,150 µg11=0 001150 kg/m3 <br />' Q = 4 3 inches water = 114 fi3/mm <br /> t=794 hours (33 days) <br />' Converting Q to m'/hour yields <br />' Q = (114 ff'/min) • (60 min/hour) • (0 0283168m3/ft ) = 193 69 m3/hour <br /> M= C • Q • t= (0 001150 kg/m') • (193 69 M3/hour) • (794 hours)= 176.86 kg of TPH-g <br /> Converting kg of TPH-g to pounds of TPH-g yields <br /> Advanced GeoEnvironmenW,Inc <br /> I <br />
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