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' Appendix G - SVE Volume-Mass Calculations <br /> AGE-NC Project No 95-0130 <br />' Page 2 of 3 <br />' 176 86 kg of TPH-g • 2 2046 lbs of TPH-g/kg of TPH-g=389.9 lbs of TPH-g <br /> Converting pounds of gasoline to gallons of gasoline yields <br />' 389 9 lbs of gas • 0 16 gal of gas/lbs of gas z 62.4 gaRons of gasoline <br />' 2 10 October 2005 - 07 November 2005 <br />' The average analytical TPH-g concentration for this time interval was determined to be 660 µg/1 <br /> (10-10-05=600µg/1 and 11-07-05=720µg/1,avg =660µg/1) The average flow rate was calculated <br />' at 3 6 inches of water or approximately 100 cubic feet per minute (nomograph), the operational <br /> period was equal to 673 hours of running time (Table 6) <br />' TPH-g(total petroleum hydrocarbons quantified as gasoline) <br /> C = 660 µg11=0 000660 kg/m3 <br /> Q z 3 60 inches water = 100 $ /min <br />' t=673 hours (28 days) <br />' Converting Q to m'/hour yields <br /> Q= (100 fl/min) • (60 min/hour) • (0 0283168m3/W) = 169 90 m3/hour <br />' M= C • Q • t= (0 000660 kg/m') • (169 90 m'/hour) • (673 hours) =75.5 kg of TPH-g <br />' Converting kg of TPH-g to pounds of TPH-g yields <br /> 75 5 kg of TPH-g• 2 2046 lbs of TPH-g/kg of TPH-g= 166.4 lbs.of TPH-g <br />' Converting pounds of gasoline to gallons of <br /> gasoline yields <br /> I166 4 lbs of gas • 0 16 gal of gas/lbs of gas = 26.6 gallons of gasoline <br /> I <br /> I <br /> i <br /> Advanced GeoEnvironmental,Inc <br />