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Nitrate Mass Balance Calculation <br /> l <br /> t Data Input: <br /> i <br /> W Effluent Quantity(Q): 420 gals/day Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream(N,,,).:.4 -N Denitrification (d): 25.0% <br /> Site Area{ 2.01 Acres Deep Perc. of Rain (R): 7.95 in/yr <br /> Result: <br /> Mass Balance(N.): 9.6 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N Waste Loading (W): 2.81 in/yr <br /> Percent of MCL Nitrate as-N 96% <br /> Equations: <br /> 1 <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find <br /> F ` yr day 7.48 gal 1 year 43,560 ftZ 1 ft (A)acre <br /> t 2.81 in/yr(site) =420 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/2.01 acres) <br /> i <br /> Nc= WNX-d)+RN,, Hantzsche-Fennemore Equation(Nc) <br /> W+R <br /> €° 9.55 mg/L-N=((2.81 in/yr x 45 mg/L-N x(1-0.25))+(7.95 in/yr x 1mg/L-N))/(2.81 in/yr+7.95 in/yr) 1 <br /> s: } <br /> Nc=Average nitrate-N concentration (mg/1) of combined effluent and rainfall percolate(9.55 mg/L-N). <br /> W=Uniform waste water loading for study area (in/yr) (2.81 inches/year). <br /> l Nw=Total nitrate-N concentration of waste water percolate (45 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the soil (25%). i <br /> R= Uniform deep percolation of rainfall (7.95 in/yr). <br /> Nb= Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 45 mg/L-N. <br /> F 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 7.95 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> i <br /> Fil <br /> F1 <br /> i <br /> NEIL O. ANDERSON <br /> F1AN D ASSOCIATES <br /> Plate 10 <br />