Laserfiche WebLink
MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> Assumptions <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br /> SVE remediation(Table 2),the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> M=C • Q • t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m') <br /> Q=extraction flow rate(m'/hr) <br /> t=operational period(hrs) <br />' The average mlet TPH-g concentration and average mlet flow <br /> rates during each tune interval were utilized for calculating <br /> the approximate mass/volume of extracted gasoline hydrocarbons <br /> 22 December to 03 January 2005 <br />' 1) The average analytical TPH-g concentration for this time interval was determined to be 710 µg11(12122/04= <br /> 700 µg/l and 01/03/05=720, avg =710 µg(I) The average flow rate was calculated at 6 2 inches of water or <br /> approximately 140 cubic feet per mmute (nomograph), the operational period was equal to 241 9 hours of <br /> running time(Table 6) <br /> C 7l 0 µg/1=0 000710 kg/m' <br /> Q 6 2 mches water 140 ft'/mm <br /> t=241 9 hours <br />' Converting Q to m'/hour yields <br /> Q=(140 ft/mm) •(60 mm/hour) •(0 0283168 m'/ft)=237 86 m'/hour <br />' M=C • Q•t=(0 000710 kg/m')•(237 86 m'/hour)• (241 9 hours)=40 85 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 40 85 kg of gas • 2 2046 lbs of gas/kg of gas=90 06 lbs of gasoline <br /> CoDvertingpounds of gasoline t6 gallons of gasoline yields <br /> 90 06 lbs of gas • 0 16 gal of gas/lbs of gas 14.41 gallons of gasoline <br />