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' MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> • <br /> Assumptions <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br /> SVE remediation(Table 2),the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> M=C• Q • t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m') <br /> Q_extraction flow rate(m'/hr) <br /> t=operational period(hrs) <br />' The average mlet TPH-g concentration and average inlet flow rates during each tune interval were utilized for calculating <br /> the approximate mass/volume of extracted gasoline hydrocarbons <br /> 03 to 20 January 2005 <br /> 1) The average analytical TPH-g concentration for this time interval was determined to be 560 µg/1(01/03/05= <br /> 720 µg/1 and 01/20/05=400, avg =560 µg/1) The average flow rate was calculated at 6 4 inches of water or <br /> approximately 145 cubic feet per minute (nomograph), the operational period was equal to 337 1 hours of <br /> running time(Table 6) <br /> C 560 µg/1=0 000560 kg/m3 <br /> Q 6 4 mches water 145 ft3/mm <br /> t=337 1 hours <br />' Converting Q to m'/hour yields <br /> Q=(145 ft3/mm)•(60 mm/hour)•(0 0283168 m3/ft)=246 36 m'/hour <br />' M=C•Q •t=(0 000560 kg/m')•(246 36 m3/hour) •(337 1 hours)—46 51 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br />' 46 51 kg of gas • 2 2046 lbs of gas/kg of gas= 102 54 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields - <br />' 102 54 lbs of gas • 0 16 gal of gas/lbs of gas 16.41 gallons of gasoline <br />