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MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br />' Assumptions <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br />' SVE remediation(Table 2),the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> M=C • Q • t <br /> where M=cumulative mass recovered(kg) <br />' C=vapor concentration(kg/m') <br /> Q=extraction flow rate(m'/hr) <br /> t=operational period(hrs) <br />' The average inlet TPH-g concentration and average inlet flow rates during each tune interval were utilized for calculating <br /> the approximate mass/volume of extracted gasoline hydrocarbons <br /> 20 January to 17 February 2005 <br />' 1) The average analytical TPH-g concentration for this time interval was determined to be 365 µg/l (0 1/20/05= <br /> 400 µg/l and 02117105=330,avg =365 µg/1) The average flow rate was calculated at 6 4 inches of water or <br /> approximately 145 cubic feet per minute (nomograph), the operational period was equal to 674 lhours of <br /> 10 running time(Table 6) <br /> C 365 gg/l=0 000365 kg/m' <br /> Q 6 4 inches water 145 ft/mm <br /> t=674 1 hours <br />' Converting Q to m'/hour yields <br /> Q=(145 ft/mug) •(60 mm/hour)•(0 0283168 m3/ft)=246 36 m3/hour <br />' M=C •Q• t=(0 000365 kg/m3)•(246 36 m'/hour) •(674 1 hours)=60 62 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> i60 62 kg of gas •2 2046 lbs of gas/kg of gas= 133 64 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 133 64 lbs of gas • 0 16 gal of gas/lbs of gas 2138 gallons of gasohne <br />