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ARCHIVED REPORTS XR0001527
Environmental Health - Public
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EHD Program Facility Records by Street Name
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C
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1419
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3500 - Local Oversight Program
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PR0544465
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ARCHIVED REPORTS XR0001527
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Last modified
5/16/2019 1:30:52 PM
Creation date
5/16/2019 1:08:43 PM
Metadata
Fields
Template:
EHD - Public
ProgramCode
3500 - Local Oversight Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0001527
RECORD_ID
PR0544465
PE
3528
FACILITY_ID
FA0005837
FACILITY_NAME
STEFANOS GASOLINE*
STREET_NUMBER
1419
Direction
E
STREET_NAME
CHARTER
STREET_TYPE
WAY
City
STOCKTON
Zip
95205
APN
15137016
CURRENT_STATUS
02
SITE_LOCATION
1419 E CHARTER WAY
P_LOCATION
01
P_DISTRICT
001
QC Status
Approved
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EHD - Public
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1 <br /> MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br />' Assumptions <br /> • Utihzmg analytical data collected from air samples(Table 4)and from field measurements collected during the <br /> SVE remediation(Table 2),the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br />' M=C • Q• t <br /> where M=cumulative mass recovered(kg) <br />' C=vapor concentration(kg/m') <br /> Q=extraction flow rate(m'/hr) <br /> t=operational period(hrs) <br />' The average inlet TPH- concentration and average inlet flow rates during each tune interval were utilized for calculator <br /> g g g g g <br /> the approximate mass/volume of extracted gasoline hydrocarbons <br /> 17 February to 08 March 2005 <br />' 1} The average analytical TPH-g concentration for this time interval was determined to be 515 gg/l (02/17/05= <br /> 330 µg/1 and 03/08/05=700, avg =515 µg/1) The average flow rate was calculated at 6 2 inches of water or <br /> approximately 140 cubic feet per minute (nomograph), the operational period was equal to 452 8 hours of <br /> lie runnmg time(Table 6) <br /> C 515 gg/l=0 000515 kg/m' <br /> Q 6 2 inches water 140 ft' <br /> /min <br /> t=452 8 hours <br /> Converting Q to m'/hour yields <br /> Q=(140 ft/mm)•(60 mm/hour)•(0 0283168 m'/ft)=237 86 m'/hour <br />' M=C• Q •t=(0 000515 kg/m') •(237 86 m'/hour)•(452 8 hours)=55 47 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br />' 55 47 kg of gas • 2 2046 lbs of gas/kg of gas= 122 29 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br />' 122 29 lbs of gas • 0 16 gal of gas/lbs of gas 19 57 gallons of gasoline <br />
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